本文實例講述了python求pi的方法,是一篇翻譯自國外網站的文章,分享給大家供大家參考。
具體實現方法如下:
#_*_ coding=utf-8 *_* ## {{{ http://code.activestate.com/recipes/578130/ (r5) def pi(places=10): """Computes pi to given number of decimal places 參數places表示要返回的pi的小數點后位數 方法:先整體擴大10**8(10的八次方)倍,然后計算完成后再縮小10的八次方倍 """ # 3 + 3*(1/24) + 3*(1/24)*(9/80) + 3*(1/24)*(9/80)*(25/168) # The numerators 1, 9, 25, ... are given by (2x + 1) ^ 2 # The denominators 24, 80, 168 are given by (16x^2 -24x + 8) extra = 8 one = 10 ** (places+extra) t, c, n, na, d, da = 3*one, 3*one, 1, 0, 0, 24 #這里的n 和d 分別為每一項的分子與分母 ,na 和 da 分別為分子和分分母后一項比前一項增加的數值 #這里的//可不是C++中的注釋,而是除的意思 while t > 1: n, na, d, da = n+na, na+8, d+da, da+32 t = t * n // d c += t return c // (10 ** extra) def picirc(radius, aspect_ratio=5): """Display the digit of pi in a circle of given radius radius:顯示的半徑 aspect_ratio:調節顯示的比率參數 """ #display_width為各行的顯示長度 display_width = int(radius * aspect_ratio + 10) pi_str = repr(pi(int(2 * radius ** 2 * aspect_ratio))) pos = 0 #cols為每一行中要顯示的數字個數 for i in range(2 * radius): cols = int(0.5 + aspect_ratio * (radius**2 - (radius-(i+0.5))**2) ** 0.5) print(pi_str[pos:pos+cols].center(display_width)) #將產生的pi數值生成的文本列表中相應的位數取出來顯示在當前行 pos += cols if __name__ == '__main__': picirc(16) ## end of http://code.activestate.com/recipes/578130/ }}}
顯示的結果為:
31415926535897932384 6264338327950288419716939937510582 0974944592307816406286208998628034825342117 06798214808651328230664709384460955058223172535940 81284811174502841027019385211055596446229489549303819644 288109756659334461284756482337867831652712019091456485669234 6034861045432664821339360726024914127372458700660631558817488152 09209628292540917153643678925903600113305305488204665213841469519415 11609433057270365759591953092186117381932611793105118548074462379962749 5673518857527248912279381830119491298336733624406566430860213949463952247 371907021798609437027705392171762931767523846748184676694051320005681271452 63560827785771342757789609173637178721468440901224953430146549585371050792279 689258923542019956112129021960864034418159813629774771309960518707211349999998 3729780499510597317328160963185950244594553469083026425223082533446850352619311 88171010003137838752886587533208381420617177669147303598253490428755468731159562 86388235378759375195778185778053217122680661300192787661119590921642019893809525 72010654858632788659361533818279682303019520353018529689957736225994138912497217 75283479131515574857242454150695950829533116861727855889075098381754637464939319 2550604009277016711390098488240128583616035637076601047101819429555961989467678 374494482553797747268471040475346462080466842590694912933136770289891521047521 62056966024058038150193511253382430035587640247496473263914199272604269922796 782354781636009341721641219924586315030286182974555706749838505494588586926 9956909272107975093029553211653449872027559602364806654991198818347977535 66369807426542527862551818417574672890977772793800081647060016145249192 17321721477235014144197356854816136115735255213347574184946843852332 3907394143334547762416862518983569485562099219222184272550254256 887671790494601653466804988627232791786085784383827967976681 45410095388378636095068006422512520511739298489608412848 86269456042419652850222106611863067442786220391949 4504712371378696095636437191728746776465757 3962413890865832645995813390478027 59009946576407895126
希望本文所述對大家的Python程序設計有所幫助。
更多文章、技術交流、商務合作、聯系博主
微信掃碼或搜索:z360901061

微信掃一掃加我為好友
QQ號聯系: 360901061
您的支持是博主寫作最大的動力,如果您喜歡我的文章,感覺我的文章對您有幫助,請用微信掃描下面二維碼支持博主2元、5元、10元、20元等您想捐的金額吧,狠狠點擊下面給點支持吧,站長非常感激您!手機微信長按不能支付解決辦法:請將微信支付二維碼保存到相冊,切換到微信,然后點擊微信右上角掃一掃功能,選擇支付二維碼完成支付。
【本文對您有幫助就好】元
