偶然在電腦里看到以前保存的這個函數,是將一個單獨字符串切分成一組字符串,這里分隔符是英文逗號“,”? 遇到其他情況只要稍加修改就好了
CREATE FUNCTION dbo.f_splitstr(
??? @str varchar(8000)
)RETURNS @r TABLE(id int IDENTITY(1, 1), value varchar(5000))
AS
BEGIN
?/* Function body */
??? DECLARE @pos int
??? SET @pos = CHARINDEX(',', @str)
??? WHILE @pos > 0
??? BEGIN
??????? INSERT @r(value) VALUES(LEFT(@str, @pos - 1))
??????? SELECT
??????????? @str = STUFF(@str, 1, @pos, ''),
??????????? @pos = CHARINDEX(',', @str)
??? END
??? IF @str > ''
??????? INSERT @r(value) VALUES(@str)
??? RETURN
END
?截圖如下

?
2011-11-15 10:15:28
今天在園子里看到另外一個實現方法,不妨借鑒一下:
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
/* by kudychen 2011-9-28 */
CREATE function [ dbo ] . [ SplitString ]
(
@Input nvarchar ( max ), -- input string to be separated
@Separator nvarchar ( max ) = ' , ' , -- a string that delimit the substrings in the input string
@RemoveEmptyEntries bit = 1 -- the return value does not include array elements that contain an empty string
)
returns @TABLE table
(
[ Id ] int identity ( 1 , 1 ),
[ Value ] nvarchar ( max ))
as
begin
declare @Index int , @Entry nvarchar ( max )
set @Index = charindex ( @Separator , @Input )
while ( @Index > 0 )
begin
set @Entry = ltrim ( rtrim ( substring ( @Input , 1 , @Index - 1 )))
if ( @RemoveEmptyEntries = 0 ) or ( @RemoveEmptyEntries = 1 and @Entry <> '' )
begin
insert into @TABLE ( [ Value ] ) Values ( @Entry )
end
set @Input = substring ( @Input , @Index + datalength ( @Separator ) / 2 , len ( @Input ))
set @Index = charindex ( @Separator , @Input )
end
set @Entry = ltrim ( rtrim ( @Input ))
if ( @RemoveEmptyEntries = 0 ) or ( @RemoveEmptyEntries = 1 and @Entry <> '' )
begin
insert into @TABLE ( [ Value ] ) Values ( @Entry )
end
return
end
使用方法
declare @str1 varchar ( max ), @str2 varchar ( max ), @str3 varchar ( max )
set @str1 = ' 1,2,3 '
set @str2 = ' 1###2###3 '
set @str3 = ' 1###2###3### '
select [ Value ] from [ dbo ] . [ SplitString ] ( @str1 , ' , ' , 1 )
select [ Value ] from [ dbo ] . [ SplitString ] ( @str2 , ' ### ' , 1 )
select [ Value ] from [ dbo ] . [ SplitString ] ( @str3 , ' ### ' , 0 )
里面還有個自增的[Id]字段哦,在某些情況下有可能會用上的,例如根據Id來保存排序等等。
?
例如根據某表的ID保存排序:
update a set a.[Order]=t.[Id]???????
from [dbo].[表] as a join [dbo].SplitString('1,2,3', ',', 1) as t on a.[Id]=t.[Value]
具體的應用請根據自己的情況來吧
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