Given a string? s , partition? s ?such that every substring of the partition is a palindrome.
Return all possible palindrome partitioning of? s .
For example, given?
s
?=?
"aab"
,
Return
[ ["aa","b"], ["a","a","b"] ]
public class Solution { public boolean[][] isPalindrome(String s) { boolean[][] isPalindrome = new boolean[s.length()][s.length()]; for (int i = 0; i < s.length(); i++) isPalindrome[i][i] = true; for (int i = 0; i < s.length() - 1; i++) isPalindrome[i][i + 1] = (s.charAt(i) == s.charAt(i + 1)); for (int length = 2; length < s.length(); length++) { for (int start = 0; start + length < s.length(); start++) { isPalindrome[start][start + length] = isPalindrome[start + 1][start + length - 1] && s.charAt(start) == s.charAt(start + length); } } return isPalindrome; } public List<List<String>> partition(String s) { boolean[][] isPalindrome= isPalindrome(s); HashMap<Integer,List<List<String>>> hm=new HashMap<Integer,List<List<String>>>(); for(int i=0;i<s.length();i++){ List<List<String>> ls=new ArrayList<List<String>>(); if(isPalindrome[0][i]){ ArrayList<String> temp=new ArrayList<String>(); temp.add(s.substring(0, i+1)); ls.add(temp); } for(int j=1;j<=i;j++){ if(isPalindrome[j][i]){ List<List<String>> l=hm.get(j-1); List<List<String>> al=new ArrayList<List<String>>(); for(List<String> temp:l){ ArrayList<String> clone=new ArrayList<String>(temp); clone.add(s.substring(j, i+1)); al.add(clone); } ls.addAll(al); } } hm.put(i,ls); } return hm.get(s.length()-1); } }
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